08s2!

Chem Tutorial and Assignment
Pass up Maths 2.1-2.3 and do maths 3.0
Gp and IRP hw
Today the most hw among all XD

Tml Class meeting for noticeboard

Chem Tutorial 3a(should be done) and Assignment 3a(by friday)
Maths 3.1(question 2)
GP File

Class Meeting TML

Chem File and GP file
Maths 2.2-2.3
Chem Test Next Wk



Class Meeting on Monday After Sch

Points of Discussion in meeting

• Board
• Fund
• Box
• Outing
• Class-T

Those who owe money please pay up!

MAths assignment 2.2 and 2.3 pls pass up to maths rep by friday!

Chemisthry tutorial 3a. pls do if u dun wan be roasted pig tmrw!!

Find about why the Donor only donated a certain amt.. ( chemisthry)

thank you! have a nice day!!

Do Chem and Chem(Tutorial and find out stuff)

IRP

CHEM AND GP FILE CHECK NEXT WK

Maths 2.2-2.3

Tml got GP work

Do Chem Tutorial Question 1b and 1c

Find out abt the Dative bonding

Do IRP

Do maths 2.3

That is all, good luck ppl

Chem Practical
Maths Practice Chapter 3
GP project work by thursday

Maths 2.2.-2.3
Phy Pg 16(if not done)

CHEM FILE CHECK AND TEST NEXT WK

Talk on Friday(for those who sign up, forgot the name liao)

Phy file(those never hand up, plz hand up)

Need a Team for Class T-Shirt( volunteer find Samantha )

ERHEM .... please please please.....$8 for the CHEM TYS .........

To all reps, if u wan to post smt... post the hw along with it -_-"
I gave the all the reps the power to post for
1.HW
2.Announcement

So if u have time to put announcement plz put hw too, thank you, at least give me a breather

Hw for wkend is
Maths 2.1-2.3(do all, if u havn't touch any)
Physic:Kinematics Page 16

Those who never pay Me $5 will have to buy their own 10 year series! The money has been submitted to teacher.


a new website for our class has been created please check http://www.freewebs.com/08s2/ =) thank you for your co-operation!

For those class rep.. you will get the link from me as soon as possible. so make SURE you CHECK your e-mail especially JACKIE =)!

Only Phy today, the kinematic wksht

Plz finish maths assignment 2.1-2.3
It is seems like it is overdue

PACK UP YOUR PHY FILES

Ok Filing is in place plz file Phy and Chem Practical Files
Today is MOSTLY ENGLISH:

DO IRP AND GP HW so u gt 2 compos to write(3 compos to those who didn't finish yellow paper)

So Good Luck

P.S. File Phy file or Chem teacher is sooo going to "praise us tml"

There are 5 ppl who never receive GP hw, plz find me asap(As soon as u read tis messenge)

Maths 2.1(if u havn't do)
Chem( Practical and Assignment)( I hate tis)
GP( Do the Wksht, pass up on Thurs)(Yellow Paper also)
Research on GP

1) finish up maths 2.1 (on summation)
2) chem assignment 2(b) - hand in on wed morning!
3) GP introduction ONLY. (yellow paper) - go thru tommorow (15/4)

reminders :
1) physics test on vectors and measurement
2) chem file (roger will confirm)

The Chem File Thing, Put on Hold, not confirm

Hw for tis wkend
GP(Yellow Paper)
Maths 2.1 Assignment
Chem Tutorial 2(b) and Assignment 2(b)(Assign is on wed)
Study for Phy test(measurement and vectors)

That is All

Today;s Hw is

GP-Go Thru Next Wk
IRP-Pass Up Tml
Maths- Do The Assignment 2.1( It seems none of us heard of tis)

Study for Phys and Chem Test Tml, Thanks XD

1) IRP - going thru tomorrow, 10/4
2) Physics vectors wksht - going thru tomorrow, 10/4
3) Maths page 2(6), supposingy do ALL. - *not sure when going thru*

ALL APPLIES ONLY TO THOSE WHO HAVEN COMPLETE THEIR WORK.

PLEASE ALSO REMEMBER to do RESPONSE FOR GP

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answers for remedial worksheet for 7/4

(page 45, Q5)

1. H2O

H = 1.0 2H 2 x 1.0 = 2.0
O = 16.0 1O 1 x 16.0 = 16.0 :. Mr = 18.0


2. CO2

C = 12.0 1C 1 x 12.0 = 12.0
O = 16.0 2O 2 x 16.0 = 32.0 :. Mr = 44.0


3. Na2CO3

Na = 23.0 2Na 2 x 23.0 = 46.0
C = 12.0 1C 1 x 12.0 = 12.0
O = 16.0 3O 3 x 16.0 = 48.0 :. Mr = 106.0


4. (NH4)2CO3

N = 14.0 2N 2 x 14.0 = 28.0
H = 1.0 8H 8 x 1.0 = 8.0
C = 12.0 1C 1 x 12.0 = 12.0
O = 16.0 3O 3 x 16.0 = 48.0 :. Mr = 96.0


5. Fe(NO3)3

Fe = 55.8 1Fe 1 x 55.8 = 55.8
N = 14.0 3N 3 x 14.0 = 42.0
O = 16.0 9O 9 x 16.0 = 144.0 :. Mr = 241.8


6. CuSO4.5H2O

Cu = 63.5 1Cu 1 x 63.5 = 63.5
S = 32.1 1S 1 x 32.1 = 32.1
O = 16.0 9O 9 x 16.0 = 144.0
H = 1.0 10H 10 x 1.0 = 10.0 :. Mr = 249.6


7. MgSO4.7H2O

Mg = 24.3 1Mg 1 x 24.3 = 24.3
S = 32.1 1S 1 x 32.1 = 32.1
O = 16.0 11O 11 x 16.0 = 176.0
H = 1.0 14H 14 x 1.0 = 14.0 :. Mr = 246.4

NOTE : ALL ANSWERS TO 1d.p!



(page 49, Q5)

(a) No. of mole of 6g of C

= 6 / 12.0
= 0.500 mol.


(b) No. of mole of 8g of S

= 8 / 32.1
= 0.249 mol.


(c) No. of mole of 112g of Fe

= 112 / 55.8
= 2.01 mol.


(d) Mr of MgO = 24.3 + 16.0 = 40.3

No. of mole of 10g of MgO

= 10 / 40.3
= 0.248 mol.


(e) Mr of Fe2O3 = (2 x 55.8) + (3 x 16.0) = 159.6

No. of mole of 16g of Fe2O3

= 16 / 159.6
= 0.100 mol.

NOTE : ALL ANSWERS TO 3s.f, write 'No. of mole' NOT 'No. of moles', write statement!



(page 50, Q7)

(a) mass of 3 moles of Na

= 3 x 23.0
= 69.0 g.


(a) Mr of H2SO4 = (2 x 1.0) + 32.1 + (4 x 16.0) = 98.1

mass of 1.5 moles of H2SO4

= 1.5 x 98.1
= 147.15
= 147 g.

NOTE : ALL ANSWERS TO 3s.f, include unit of mass in answer (i.e. grams), write statement!



(page 50, Q8)
[(a) is example in paper!]

(b) No. of mole of O = (6.02 x 10^23) / (6.02 x 10^23) = 1 mol

:. mass of O = 1 x 16.0 = 16.0 g.


(c) No. of mole of H2O = (3.01 x 10^23) / (6.02 x 10^23) = 0.5000 mol

:. mass of H2O = 0.5000 x [(2 x 1.0) + 16.0] = 9.00 g.


(d) No. of mole of CH4 = (2.01 x 10^23) / (6.02 x 10^23) = 0.3333 mol

:. mass of O = 0.3333 x [12.0 + 4(1.0)] = 5.33 g.


(e) No. of mole of CO2 = (4.01 x 10^23) / (6.02 x 10^23) = 0.6661 mol

:. mass of CO2 = 0.6661 x [12.0 + 2(16.0)] = 29.3 g.

NOTE : include units, ALL INTERMEDIATE ANSWERS TO 4s.f, ALL ANSWERS TO 3s.f!



(page 51, Q9)
[(a) is example in paper!]

*(b) No. of mole of 8g of O2(g) = 8 / 2(16.0) = 0.2500 mol

*take note O2 is equivalent to 2O atoms!*

No. of mole of O atoms = 2 x 0.2500 = 0.5000 mol

:. No. of O atoms = 0.5000 x 6.02 x 10^23 = 3.01 x 10^23 g


(c) No. of mole of 8g of O2(g) = 8 / 2(16.0) = 0.2500 mol

No. of molecules of O2(g) = 0.2500 x 6.02 x 10^23 = 1.51 x 10^22 g


(d) No. of mole of 35g of Cl2(g) = 35 / 2(35.5) = 0.4930 mol

No. of molecules of O2(g) = 0.4930 x 6.02 x 10^23 = 2.97 x 10^23 g


(e) No. of mole of 3g of H2O = 3 / [(2 x 1.0) + 16.0] = 0.1667 mol

No. of molecules of H2O = 0.1667 x 6.02 x 10^23 = 1.00 x 10^23 g

NOTE : ALL ANSWERS TO 3s.f, intermediate answers to 4s.f, write 'No. of mole' NOT 'No. of moles', write statement!



(page 51, Q10)

Hydrogen, H2 (4 mole) - volume = 4 x 24.0 = 96.0 dm3

Oxygen, O2 (8 mole) - volume = 8 x 24.0 = 192.0 dm3

Carbon dioxide, CO2 (0.5 mole) - volume = 0.5 x 24.0 = 12.0 dm3

Nitrogen, N2 (0.001 mole) - volume = 0.001 x 24.0 = 0.0240 dm3

NOTE : final answer to 3s.f, show working! WRITE UNITS!



(page 52, Q11)

Hydrogen, H2 (24 dm3)

no. of mole = 24.0 / 24.0 = 1 mol

Mr = 2.0

mass = 2.0 g


Oxygen, O2 (48 dm3)

no. of mole = 48.0 / 24.0 = 2 mol

Mr = 32.0

mass = 64.0 g


Carbon dioxide, CO2 (6 dm3)

no. of mole = 6.0 / 24.0 = 0.250 mol

Mr = 44.0

mass = 11.0 g


Nitrogen, N2 (48 cm3) *convert!*

no. of mole = (48 / 1000) / 24.0 = 2 x 10^-3 mol

Mr = 28.0

mass = 0.0560 g

NOTE : all answers to 3s.f, include UNITS!



(page 53, Q16)

(a) concentration = 0.5 / (250 / 1000)

= 2.00 mol/dm3


(b) no. of mole of NaOH = 2 / (23.0 + 16.0 + 1.0) = 0.05000

concentration = 0.05000 / (50 / 1000)

= 1.00 mol/dm3


(c) no. of mole of Na2SO4 = 35.5 / [2(23.0) + 32.1 + 4(16.0)] = 0.2498

concentration = 0.2498 / (500 / 1000)

= 0.500 mol/dm3

NOTE : final answerUNITS!



(page 53, Q17)

(a) no. of mole of HCl

= 0.5mol/dm3
= 1.00 mol


(b) no. of mole of NaOH

= 2.5 mol/dm3 x 4 dm3
= 10.0 mol


(c) no. of mole of H2SO4

= 2.5 mol/dm3 x 500 / 1000 dm3
= 1.25 mol


(d) no. of mole of HNO3

= 1.0 mol/dm3 x 400 / 1000 dm3
= 0.400 mol

NOTE : answers to 3s.f!



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sorry for untidyness and please double check if the answers above are right.(:

happy 17th birthday to our assistant class rep!